Question

\(4^{x+1}=8^2\)

Answer 1

\(4^{^{ }x+1}=8^2\)

\(\Rightarrow2^{2\left(x+1\right)}=2^6\)

\(\Rightarrow2\left(x+1\right)=6\)

\(\Rightarrow x+1=6\div2=3\)

\(\Rightarrow x=3-1=2\)

vậy x=2

Answer 2

\(4^{x+1}=8^2\)

\(4^{x+1}=64\)

\(4^3=64\)

=> x = 3 - 1

=> x = 2

Answer 3

$4^{x+1}=8^2$

⇒\(\left(2^2\right)^{x+1}\) =\(\left(2^3\right)^2\)

⇒\(2^{2\left(x+1\right)}\) =\(2^6\)

⇒2(x+1)=6

⇒x+1=6:2

⇒x+1=3

⇒x=3-1

⇒x=2

Vậy x=2

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