\(\left(\dfrac{2}{3-x}\right)^2=49\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{2}{3}-x=7\\\dfrac{2}{3}-x=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{19}{3}\\x=\dfrac{23}{3}\end{matrix}\right.\)
Đề chả biết đâu vào đâu, \(\left(\dfrac{2}{3-x}\right)hay\left(\dfrac{2}{3}-x\right)\) thế, LÀM ƠN ghi đề rõ ra giùm cái ?
Số 2 -_- bữa sau oánh hộ cái đề ra nhá :))
\(\left(\dfrac{2}{3}-x\right)^2=49\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{2}{3}-x=7\\\dfrac{2}{3}-x=-7\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{19}{3}\\x=\dfrac{23}{3}\end{matrix}\right.\)
Vậy x nhận hai giá trị là : \(x=-\dfrac{19}{3}\) hoặc \(x=\dfrac{23}{3}\)
Ta có :
\(\left(\dfrac{2}{3}-x\right)^2=49\)
\(\Rightarrow\left[{}\begin{matrix}\left(\dfrac{2}{3}-x\right)^2=7^2\\\left(\dfrac{2}{3}-x\right)^2=\left(-7\right)^2\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}\dfrac{2}{3}-x=7\\\dfrac{2}{3}-x=-7\end{matrix}\right.\)
\(TH1:\)
\(\dfrac{2}{3}-x=7\)
\(x=\dfrac{2}{3}-7\)
\(x=\dfrac{-19}{3}\)
\(TH2:\)
\(\dfrac{2}{3}-x=-7\)
\(x=\dfrac{2}{3}-\left(-7\right)\)
\(x=\dfrac{23}{3}\)
Vậy \(x\in\left\{\dfrac{-19}{3};\dfrac{23}{3}\right\}\) là giá trị cần tìm
~ Học tốt ~
\(\left(\dfrac{2}{3}-x\right)^2=49\)
\(\Leftrightarrow\)\(\left(\dfrac{2}{3}-x\right)^2=7^2\)
\(\Leftrightarrow\)\(\dfrac{2}{3}-x=7\)
\(\Leftrightarrow\)\(x=\dfrac{2}{3}-7\)
\(\Rightarrow\)\(x=\dfrac{-19}{3}\)
Vậy x= \(\dfrac{-19}{3}\)
(\(\dfrac{2}{3}\) -x)2=49
\(\left[{}\begin{matrix}\left(\dfrac{2}{3}-x\right)^2\\\left(\dfrac{2}{3}-x\right)^2=\left(-7\right)^2\end{matrix}\right.=7^2\)
\(\left[{}\begin{matrix}\dfrac{2}{3}-x=7\\\dfrac{2}{3}-x=-7\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=\dfrac{-19}{3}\\x=\dfrac{23}{3}\end{matrix}\right.\)
Vậy x=\(\dfrac{-19}{3}\) hoặc x=\(\dfrac{23}{3}\)