đk x# 1 x#0 x> 0
Rgọn : P= \(\frac{x}{\sqrt{x}-1}\)- \(\frac{2x-\sqrt{x}}{x-\sqrt{x}}\)
= \(\frac{x\sqrt{x}-\left(2x-\sqrt{x}\right)}{\sqrt{x}\left(\sqrt{x}-1\right)}\)
= \(\frac{\sqrt{x}\left(x-2\sqrt{x}+1\right)}{\sqrt{x\left(\sqrt{x}-1\right)}}\)
=\(\sqrt{x}-1\)
ta có x= 4 +\(2\sqrt{3}\)
= 3 +2\(\sqrt{3}\)+1
= \(\left(\sqrt{3}+1\right)^2\)
Thay vào P ta dc
\(\sqrt{\left(\sqrt{x}-1\right)^2}\)-1
= \(\sqrt{x}-1-1\)
= \(\sqrt{x}-2\)
Đúng 0
Bình luận (0)
