Question

1/2a-1.\(\sqrt{25a^{\text{4}}-100a^5+100a^6}\)

Answer 1

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Answer 2

\(\frac{1}{2a-1}.\sqrt{25a^4-100a^5+100a^6}\)

= \(\frac{1}{2a-1}.\sqrt{25a^4\left(1-4a+4a^2\right)}\)

= \(\frac{1}{2a-1}.5a^2\sqrt{\left(1-2a\right)^2}\)

= \(\frac{5a^2}{2a-1}.\left(1-2a\right)\)

= \(-5a^2\)