Đề bài yêu cầu tính hay sao em?
Ta có: \(10-\left[\left(8^2-48\right)\cdot5+\left(2^3\cdot10+8\right)\right]:28\)
\(=10-\left[16\cdot5+\left(8\cdot10+8\right)\right]:28\)
\(=10-\left(80+80+8\right):28\)
\(=10-168:28\)
\(=10-6=4\)
\(10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]:28\)
\(=10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[16.5+\left(80+8\right)\right]:28\)
\(=10-\left[16.5+88\right]:28\)
\(=10-\left[80+88\right]:28\)
\(=10-168:28\)
\(=10-6=4\)
\(10-\left[\left(8^2-48\right).5+\left(2^3.10+8\right)\right]:28\)
\(=10-\left[\left(64-48\right).5+\left(8.10+8\right)\right]:28\)
\(=10-\left[16.5+8.\left(10+1\right)\right]:28\)
\(=10-\left[80+8.11\right]:28\)
\(=10-\left[80+88\right]:28\)
\(=10-168:28\)
\(=10-6\)
\(=4\)
