Ta có: \(L=\dfrac{N}{2}\cdot3,4\Rightarrow N=\dfrac{L\cdot2}{3,4}=\dfrac{5100\cdot2}{3,4}=3000\left(nu\right)\)
Ta có: \(T=20\%\cdot3000=600\left(nu\right)\)
Mà: \(A=T=600;G=X\)
Ta có: \(N=A+T+G+X\)
\(\Rightarrow N=2A+2G\\ \Rightarrow3000=\left(2\cdot600\right)+2G\\ \Rightarrow2G=3000-1200\\ \Rightarrow2G=1800\\ \Rightarrow G=\dfrac{1800}{2}=900\left(nu\right)\)
Vậy: \(T=A=600nu;G=X=900nu.\)
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