Câu hỏi của Tamduc

a: \(A=\dfrac{\sqrt{x}\left(\sqrt{x}-3\right)-x-9}{x-9}:\dfrac{2\sqrt{x}-1-\sqrt{x}+3}{\sqrt{x}\left(\sqrt{x}-3\right)}\)\(=\dfrac{-3\sqrt{x}-9}{x-9}\cdot\dfrac{\sqrt{x}-3}{\sqrt{x}+2}\)\(=\dfrac{-3}{\sqrt{x}+2}\)b: Để A nguyên thì \(-3⋮\sqrt{x}+2\)=>\(\sqrt{x}+2=3\)=>x=1Câu trả lời: a: \(A=\dfrac{\sqrt{x}\left(\sqrt{x}-3\right)-x-9}{x-9}:\dfrac{2\sqrt{x}-1-\sqrt{x}+3}{\sqrt{x}\left(\sqrt{x}-3\right)}\)\(=\dfrac{-3\sqrt{x}-9}{x-9}\cdot\dfrac{\sqrt{x}-3}{\sqrt{x}+2}\)\(=\dfrac{-3}{\sqrt{x}+2}\)b: Để A nguyên thì \(-3⋮\sqrt{x}+2\)=>\(\sqrt{x}+2=3\)=>x=1