Question

Answer 1

\(x^2+x-6=0\)

\(x^2+2x-3x=0\)

\(\left(x+3\right).\left(x-2\right)=0\)

\(=>\left[{}\begin{matrix}x+3=0\\x-2=0\end{matrix}\right.=>\left[{}\begin{matrix}x=-3\\x=2\end{matrix}\right.\)

Vậy

Answer 2

=>(x+3)(x-2)=0

=>x=-3 hoặc x=2