Question

Answer 1

 

\(a,W_d=\dfrac{0,1.6^2}{2}=1,8J\\ W_t=0,1.10.8=8J\\ W=W_t+W_d=9,8J\)

\(b,Ta.có\\ mgh_{max}=\dfrac{mv^2}{2}\\ \Leftrightarrow0,1.10.h_{max}=\dfrac{0,1.6^2}{2}\\ \Rightarrow hmax=1,8m\)

 \(c,W_t=W_d\\ \Leftrightarrow8=\dfrac{mv^2}{2}\Leftrightarrow8=\dfrac{0,1.v^2}{2}\\ \Rightarrow v=12,6m/s\\ d,\Delta W=\dfrac{1}{2}m\left(v_2^2-v_1^2\right)=3,2J\\ F_{ctb}=\dfrac{\Delta W}{S}=\dfrac{3,2}{0,03}=106,\left(6\right)N\)