Question

Answer 1

\(n_{H_2}=\dfrac{2,24}{22,4}=0,1\left(mol\right)\)

PTHH: Zn + 2HCl --> ZnCl₂ + H₂

          0,1<--0,2<-------0,1<--0,1

=> m_Zn = 0,1.65 = 6,5 (g)

=> \(\left\{{}\begin{matrix}\%m_{Zn}=\dfrac{6,5}{8,5}.100\%=76,47\%\\\%m_{MgO}=\dfrac{8,5-6,5}{8,5}.100\%=23,53\%\end{matrix}\right.\)

\(n_{MgO}=\dfrac{8,5-6,5}{40}=0,05\left(mol\right)\)

PTHH: MgO + 2HCl --> MgCl₂ + H₂O

          0,05->0,1-------->0,05

=> n_HCl = 0,2 + 0,1 = 0,3 (mol)

=> \(aM=C_M=\dfrac{0,3}{0,2}=1,5M\)

A chứa \(\left\{{}\begin{matrix}ZnCl_2:0,1\left(mol\right)\\MgCl_2:0,05\left(mol\right)\end{matrix}\right.\)

=> \(\left\{{}\begin{matrix}C_{M\left(ZnCl_2\right)}=\dfrac{0,1}{0,2}=0,5M\\C_{M\left(MgCl_2\right)}=\dfrac{0,05}{0,2}=0,25M\end{matrix}\right.\)