Question

Answer 1

a: ĐKXĐ: \(a\notin\left\{0;-3;3\right\}\)

b: \(B=\dfrac{\left(a+3\right)^2}{2a\left(a+3\right)}\cdot\dfrac{a^2-9-6a+18}{\left(a-3\right)\left(a+3\right)}\)

\(=\dfrac{\left(a-3\right)^2}{2a\left(a-3\right)}=\dfrac{a-3}{2a}\)