Question

Answer 1

\(\widehat{A}+\widehat{B}+\widehat{C}=180^0\\ \Rightarrow\widehat{B}+\widehat{C}=180^0-90^0=90^0\)

Mà \(\widehat{B}-\widehat{C}=20^0\Leftrightarrow\left\{{}\begin{matrix}\widehat{B}=\left(90^0+20^0\right):2=55^0\\\widehat{C}=90^0-55^0=35^0\end{matrix}\right.\)

Answer 2

\(\widehat{B}=55^0\)

\(\widehat{C}=35^0\)