\(\sqrt{12-\sqrt{108}}-\sqrt{7-\sqrt{48}}\)
\(=\sqrt{12-6\sqrt{3}}-\sqrt{7-4\sqrt{3}}\)
\(=\sqrt{9-6\sqrt{3}+3}-\sqrt{4-4\sqrt{3}+3}\)
\(=\sqrt{\left(3-\sqrt{3}\right)^2}-\sqrt{\left(2-\sqrt{3}\right)^2}\)
\(=\left|3-\sqrt{3}\right|-\left|2-\sqrt{3}\right|\)
\(=3-\sqrt{3}-2+\sqrt{3}\)
\(=1\)
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Ta có: \(\sqrt{12-\sqrt{108}}-\sqrt{7-\sqrt{48}}\)
\(=\sqrt{12-2\sqrt{27}}-\sqrt{7-4\sqrt{3}}\)
\(=3-\sqrt{3}-2+\sqrt{3}\)
=1
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