tổng cộng có: 9*1/2= 9/2(l)

chia đều cho 4 người nên mỗi người có:(9/2)/4=9/8(= 1.125 nhưng nên dùng phân số)

a)PTHHH : Ca(OH)₂ + Na₂CO₃ \(\rightarrow\) CaCO₃ + 2NaOH

b) Theo PTHH ta có \(n_{NaOH}=2n_{Na_2CO_3}=0,25\cdot2=0.5\left(mol\right)\)

Số mol NaOH thu được từ 0,5 mol Natri Cabonat là

\(m_{Na_2CO_3}=M_{Na_2CO_3}\cdot n_{Na_2CO_3}=106\cdot0,5=53\left(g\right)\)

2FeS + 10H₂SO₄ \(\rightarrow\) Fe₂(SO₄)₃ + 9SO₂ + 10H₂O

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