Câu trả lời:
|2x-1|+3x=15
Ta có: |2x-1|=2x-1 <=> 2x-1 \(\ge\) 0 <=> x \(\ge\) 1/2
|2x-1|=-(2x-1)=-2x+1 <=> -2x+1 < 0 <=> -2x<-1 <=> x < 1/2
Nếu x \(\ge\) 1/2 thì (1) <=> 2x-1+3x=15 <=> 5x=16 <=> x=16/5
Nếu x < 1/2 thì (1) <=> -2x+1+3x=15 <=> x=14
Vậy x \(\in\) {16/5;14}