\(\frac{2\left(x+4\right)}{\left(\sqrt{x}+1\right)\left(x-4\right)}\)+\(\frac{\sqrt{x}}{\sqrt{x}+1}\)+\(\frac{8}{4-\sqrt{x}}\)

a, tìm đkxđ rút gọn

Rewrite the sentences using the full form of be in the following setences

1 I'm a student

2 They're playing football in the stadium

M = \(\frac{x\sqrt{x}-1}{x-\sqrt{x}}\)-\(\frac{x\sqrt{x}+1}{x+\sqrt{x}}\)+\(\frac{x+1}{\sqrt{x}}\)

\(\left(\frac{2\sqrt{x}}{\sqrt{x}+3}+\frac{\sqrt{x}}{\sqrt{x}-3}-\frac{3x+3}{x-9}\right)\).\(\left(\frac{2\sqrt{x}-2}{\sqrt{x}-3}-1\right)\)

\(\frac{1}{2\sqrt{x+3}-1}\).\(\frac{1}{2\left(\sqrt{x+3}+1\right)}\)

(\(\frac{3}{1-x}\).\(\frac{1}{\sqrt{x}+1}\)):\(\frac{1}{\sqrt{x}+1}\)

một tam giác vuông có cạnh huyền là6.15 cm.đường cao ứng với cạnh huyền la 3 cm.tính các cạnh góc vuông?

A=\(\left(\frac{\sqrt{6}-\sqrt{5}}{\sqrt{2}-1}+\frac{5-\sqrt{5}}{\sqrt{5}-1}\right):\frac{2}{\sqrt{5}-\sqrt{3}}\)

B=\(\frac{4+\sqrt{2}-\sqrt{3}-\sqrt{6}+\sqrt{8}}{2+\sqrt{2}-\sqrt{3}}\)

A=\(\frac{4+\sqrt{2}-\sqrt{3}-\sqrt{6}+\sqrt{8}}{2+\sqrt{2}-\sqrt{3}}\)

B=\(\sqrt{2}.\left(\sqrt{3}+1\right).\sqrt{2-\sqrt{3}}\)

\(\frac{x}{x-2}\)+\(\frac{x+2}{x}\)>2