sin²x - sinx = 0 ⇔ sinx(sinx - 1) = 0

Th1. sinx=0 \(\Leftrightarrow\) x=kπ \(\left(k\in Z\right)\)

Th2.  sinx=1\(\Leftrightarrow\)  x= \(\dfrac{\text{π}}{2}\) + \(\text{k 2 π}\)\(\left(k\in Z\right)\)
Vậy phương trình có hai họ nghiệm là: 
- \(x=k\pi\) và \(x=\dfrac{\pi}{2}+k2\pi\)  với \(\left(k\in Z\right)\)

Mơn mi nhiều nghen

Iu mi lắm

Mark the letter A, B, C or D to indicate the correct answer to each of the following questions.

Question 9: The more effect you put in this project, ______.

A. the results are more and more satisfying

B. the more satisfaction the results are

C. the more satisfying the results are

D. the more satisfied are you