nam tử hán bật đèn học típ

Ta có: A=\(\frac{14^{15}+3}{14^{15}+3}\) = 1 

B=\(\frac{14^{16}+5}{14^{17}+5}\) < 1 => B<1=A => B<A.

A=\(\frac{2005^{2005}+1}{2005^{2006}+1}\) < 1 => \(\frac{2005^{2005}+1}{2005^{2006}+1}\) < \(\frac{2005^{2005}+1+2004}{2005^{2006}+1+2004}\) = \(\frac{2005^{2005}+2005}{2005^{2006}+2005}\)= \(\frac{2005.\left(2005^{2004}+1\right)}{2005.\left(2005^{2005}+1\right)}\) = \(\frac{2005^{2004}+1}{2005^{2005}+1}\) = B => A<B.

Chia đôi.

(2n+2)(2n+2)(2n+3)(2n+4):12]+(n+1)