HOC24
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\(\dfrac{2x+1}{6}=-\dfrac{1}{2}\)\(\Leftrightarrow\dfrac{2x+1}{6}=-\dfrac{3}{6}\)
\(\Leftrightarrow2x+1=-3\)
\(\Leftrightarrow2x=-4\)
\(\Leftrightarrow x=-2\)
\(c`3,4.0,7+3,4.0,3-0,4=3,4.\left(0,7+0,3\right)-0,4=3,4.10-0,4=34-0,4=33,6\)
\(d`\left(1-\dfrac{1}{2}+\dfrac{3}{4}\right)-\left(\dfrac{1}{2}+1\dfrac{3}{4}-3\right)=\left(1-\dfrac{1}{2}+\dfrac{3}{4}\right)-\left(\dfrac{1}{2}+\dfrac{7}{4}-3\right)=1-\dfrac{1}{2}+\dfrac{3}{4}-\dfrac{1}{2}-\dfrac{7}{4}+3=\left(1+3\right)+\left(-\dfrac{1}{2}-\dfrac{1}{2}\right)+\left(\dfrac{3}{4}-\dfrac{7}{4}\right)=4+\left(-1\right)+\left(-1\right)=2\)
a, Ta có pt : \(Zn+2HCL->ZnCl_2+H_2\)
b, \(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\)
Theo pt (ở câu a ) , có : \(n_{Zn}=n_{H_2}=0,1\left(mol\right)\)
\(V_{H_2\left(DKTC\right)}=0,1\times22,4=2,24\left(l\right)\)
\(\left|x^2-1\right|=2x+1\left(dk:2x+1\ge0\Leftrightarrow2x\ge-1\Leftrightarrow x\le-\dfrac{1}{2}\right)\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2-1=2x+1\\x^2-1=-2x-1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2-1-2x-1=0\\x^2-1+2x+1=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2-2x-2=0\\x^2+2x=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x^2-2x-2+3=3\\x.\left(x+2\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(x-1\right)^2=3\\\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(x-1^2\right)-\left(\sqrt{3}\right)^2=0\\\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left(x-1-\sqrt{3}\right).\left(x-1+\sqrt{3}\right)=0\\\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x=1-\sqrt{3}\left(loai\right)\\x=1+\sqrt{3\left(loai\right)}\end{matrix}\right.\\\left[{}\begin{matrix}x=0\left(loai\right)\\x=-2\left(tm\right)\end{matrix}\right.\end{matrix}\right.\)
Vậy x = -2
tổng vận tốc 2 xe là :
45 + 43 = 88 ( km/h )
thời gian 2 xe gặp nhau là :
220 : 88 = 2,5 ( h ) = 2h30p
hai xe gặp nhau lúc :
8h15p + 2h30p = 10h45p