a) \(x\cdot\dfrac{14}{27}=-\dfrac{7}{9}\)

\(x=\left(-\dfrac{7}{9}\right):\dfrac{14}{27}\)

\(x=\left(-\dfrac{7}{9}\right)\cdot\dfrac{27}{14}\)

\(x=-\dfrac{3}{2}\)

b) \(\left(-\dfrac{5}{9}\right):x=\dfrac{2}{3}\)

\(x=\left(-\dfrac{5}{9}\right)\cdot\dfrac{3}{2}\)

\(x=-\dfrac{5}{6}\)

c) \(\dfrac{2}{5}:x=\dfrac{1}{16}:0,125\)

\(\dfrac{2}{5}:x=\dfrac{1}{16}\cdot8\)

\(\dfrac{2}{5}:x=\dfrac{1}{2}\)

\(x=\dfrac{2}{5}\cdot2\)

\(x=\dfrac{4}{5}\)

d) \(-\dfrac{5}{12}x=\dfrac{2}{3}-\dfrac{1}{2}\)

\(-\dfrac{5}{12}x=\dfrac{4}{6}-\dfrac{3}{6}\)

\(-\dfrac{5}{12}x=\dfrac{1}{6}\)

\(x=\dfrac{1}{6}\cdot\left(-\dfrac{12}{5}\right)\)

\(x=-\dfrac{2}{5}\)

2) \(\sqrt{\left[\left(-2\right)^6\right]}=\sqrt{64}=8\)

6) \(2\sqrt{3}+\sqrt{\left[\left(2-\sqrt{3}\right)^2\right]=2\sqrt{3}+2-\sqrt{3}=2+\sqrt{3}}\)

\(5\left(3x+5\right)-4\left(2x-3\right)=5x+3\left(2x+12\right)+1\)

\(15x+25-8x-12=5x+6x+36+1\)

\(\left(15x-8x\right)+\left(25+12\right)=11x+37\)

\(7x+37=11x+37\)

\(7x-11x=37-37\)

\(-4x=0\)

`=>x=0`

\(M=\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right)\cdot230\dfrac{1}{25}+46\dfrac{3}{4}\)

\(M=\left(\dfrac{53}{4}-\dfrac{59}{27}-\dfrac{65}{6}\right)\cdot\dfrac{5751}{25}+\dfrac{187}{4}\)

\(M=\dfrac{25}{108}\cdot\dfrac{5751}{25}+\dfrac{187}{4}\)

\(M=\dfrac{5751}{108}+\dfrac{187}{4}=\dfrac{213}{4}+\dfrac{187}{4}\)

\(M=\dfrac{400}{4}=100\)

\(N=\left(1\dfrac{3}{7}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)\)

\(N=\left(\dfrac{10}{7}+\dfrac{10}{3}\right):\left(\dfrac{37}{3}-\dfrac{100}{7}\right)\)

\(N=\dfrac{100}{21}\cdot\left(-\dfrac{21}{41}\right)\)

\(N=-\dfrac{100}{41}\)

b) Vì \(-\dfrac{100}{41}< 1\)

mà \(100>1\)

`=>`\(100>-\dfrac{100}{41}\)

Wao 

tích thừa cái kìa cj :D

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