1.was

2.would

3.liked

4.said

5.were

6.could

7.was

8.costs

9.said

10.had just got

1.b

2.d

3.c

4.b

5.d

6.c

7.d

8.a

9.c

10.b

=\(\left(\dfrac{\sqrt{x}}{3+\sqrt{x}}+\dfrac{9+x}{\left(3-\sqrt{x}\right).\left(3+\sqrt{x}\right)}\right).\left(3\sqrt{x}-x\right)\)

=\(\left(\dfrac{\sqrt{x}.\left(3-\sqrt{x}\right)}{\left(3+\sqrt{x}\right)\left(3-\sqrt{x}\right)}+\dfrac{9+x}{\left(3+\sqrt{x}\right)\left(3-\sqrt{x}\right)}\right).\left(3\sqrt{x}-x\right)\)

=\(\dfrac{3\sqrt{x}-x+9+x}{\left(3+\sqrt{x}\right)\left(3-\sqrt{x}\right)}.\left(3\sqrt{x}-x\right)\)

=\(\dfrac{3\sqrt{x}+9}{\left(3+\sqrt{x}\right)\left(3-\sqrt{x}\right)}.\left(3\sqrt{x}-x\right)\)

=\(\dfrac{3\left(\sqrt{x}+3\right).\sqrt{x}\left(3-\sqrt[]{x}\right)}{\left(3+\sqrt{x}\right)\left(3-\sqrt{x}\right)}\)

=\(3\sqrt{x}\)

=\(\left(\dfrac{5\sqrt{x}-6}{\left(\sqrt{x}-3\right).\left(\sqrt{x}+3\right)}-\dfrac{2}{\sqrt{x}+3}\right):\left(\dfrac{x-9}{x-9}+\dfrac{6}{x-9}\right)\)

=\(\left(\dfrac{5\sqrt{x}-6-2\sqrt{x}+6}{x-3}\right):\left(\dfrac{x-9+6}{x-9}\right)\)

=\(\left(\dfrac{3\sqrt{x}}{x-3}\right):\dfrac{x-3}{x-9}\)

=\(\dfrac{3\sqrt{x}}{x-3}.\dfrac{x-9}{x-3}\)

=\(\dfrac{3x+9}{\sqrt{x}-3}\)

d.P>2

(=)\(\dfrac{2x}{x-2}>2\)

(=)\(\dfrac{2x}{x-2}-2>0\)

(=)\(\dfrac{2x}{x-2}-\dfrac{2\left(x-2\right)}{x-2}>0\)

(=)\(\dfrac{2x}{x-2}-\dfrac{2x-4}{x-2}>0\)

(=)\(\dfrac{2x-2x+4}{x-2}>0\)

(=)\(\dfrac{4}{x-2}>0\)

(=)x-2>0

(=)x>2

P rút gọn bằng mấy á

A=\(\left(\dfrac{4}{\sqrt{x}-1}-\dfrac{\sqrt{x}-2}{\left(\sqrt{x}-1\right).\left(\sqrt{x}-2\right)}\right).\left(\dfrac{\sqrt{x}-1}{x^2}\right)\)

=\(\left(\dfrac{4.}{\sqrt{x}-1}-\dfrac{1}{\sqrt{x}-1}\right).\left(\dfrac{\sqrt{x}-1}{x^2}\right)\)

=\(\dfrac{4-1}{\sqrt{x}-1}.\dfrac{\sqrt{x}-1}{x^2}\)

=\(\dfrac{3.\left(\sqrt{x}-1\right)}{\left(\sqrt{x}-1\right).x^2}\)

=\(\dfrac{3}{x^2}\)

1.residential

2.financial

3.mountainous

4.performance

5.famous

6.various

7.reasonable

8.cultural

9.information

10.exhibition