Tính giá trị biểu thức \(\dfrac{3}{12}+0,6-\Big(\dfrac{4}{3}+\dfrac{1}{4}\Big)\).
\(\dfrac{-14}{15}.\)\(\dfrac{-13}{15}.\)\(\dfrac{10}{15}.\)\(\dfrac{-11}{15}.\)Hướng dẫn giải:\(\dfrac{3}{12}+0,6-\Big(\dfrac{4}{3}+\dfrac{1}{4}\Big)\)
\(=\dfrac{1}{4}+\dfrac{3}{5}-\dfrac{4}{3}-\dfrac{1}{4}\)
\(=\dfrac{3}{5}-\dfrac{4}{3}=\dfrac{9}{15}-\dfrac{20}{15}\)
\(=\dfrac{-11}{15}.\)
