Sau khi thực hiện phép tính \(\dfrac{3x^2-6x+3}{4x+4}.\dfrac{2x^2-2}{3\left(x-1\right)^2}\), ta có kết quả là
\(\frac{x-1}{2}\).\(\dfrac{x+1}{4}\).\(\dfrac{x-1}{4\left(x+1\right)}\).\(\dfrac{x-1}{12}\).Hướng dẫn giải:\(\dfrac{3x^2-6x+3}{4x+4}.\dfrac{2x^2-2}{3\left(x-1\right)^2}\)
\(=\dfrac{3\left(x^2-2x+1\right)}{4\left(x+1\right)}.\dfrac{2\left(x-1\right)\left(x+1\right)}{3\left(x-1\right)^2}\)
\(=\dfrac{6\left(x-1\right)^3\left(x+1\right)}{4.3\left(x+1\right)\left(x-1\right)^2}\)
\(=\dfrac{x-1}{2}\).
