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\(\int e^{3-2x}\text{d}x=-2e^{3-2x}+C\).\(\int e^{3-2x}\text{d}x=-\frac{1}{3-2x}e^{3-2x}+C\).\(\int e^{3-2x}\text{d}x=-\frac{1}{2}e^{3-2x}+C\).\(\int e^{3-2x}\text{d}x=\frac{1}{2}e^{3-2x}+C\).Hướng dẫn giải:\(\int e^{3-2x}\text{d}x=-\frac{1}{2}\int e^{3-2x}\left(-2\text{dx}\right)\text{ }=-\frac{1}{2}\int e^{3-2x}\text{d}\left(3-2x\right)=-\frac{1}{2}e^{3-2x}+C\).