Cho biết \(\dfrac{3}{4}x-\dfrac{2}{3}x=\dfrac{2}{7}.\dfrac{1}{6}+\dfrac{5}{7}.\dfrac{1}{6}\). Giá trị của x là
\(2\). \(\dfrac{1}{2}\). \(\dfrac{1}{6}\). \(\dfrac{1}{12}\). Hướng dẫn giải:\(\dfrac{3}{4}x-\dfrac{2}{3}x=\dfrac{2}{7}.\dfrac{1}{6}+\dfrac{5}{7}.\dfrac{1}{6}\)
\(\Leftrightarrow x\left(\dfrac{3}{4}-\dfrac{2}{3}\right)=\dfrac{1}{6}\left(\dfrac{2}{7}+\dfrac{5}{7}\right)\)
\(\Leftrightarrow x.\dfrac{9-8}{12}=\dfrac{1}{6}\)
\(\Leftrightarrow x.\dfrac{1}{12}=\dfrac{1}{6}\)
\(\Leftrightarrow x=\dfrac{1}{6}:\dfrac{1}{12}\)
\(\Leftrightarrow x=2\)
