\(\left(y+2\dfrac{1}{3}\right)+6\%=\left(2\dfrac{1}{3}+6\%\right)+2019\)
\(\left(y+\dfrac{7}{3}\right)+\dfrac{3}{50}=\left(\dfrac{7}{3}+\dfrac{3}{50}\right)+2019\)
\(\left(y+\dfrac{7}{3}\right)+\dfrac{3}{50}=\dfrac{359}{150}+2019\)
\(\left(y+\dfrac{7}{3}\right)+\dfrac{3}{50}=\dfrac{303209}{150}\)
\(y+\dfrac{7}{3}=\dfrac{303209}{150}-\dfrac{3}{50}\)
\(y+\dfrac{7}{3}=\dfrac{6064}{3}\)
\(y=\dfrac{6064}{3}-\dfrac{7}{3}\)
\(y=2019\)
\(\text{Cách 2}\) \(\left(y+2\dfrac{1}{3}\right)+6\%=\left(2\dfrac{1}{3}+6\%\right)+2019\)
\(\left(y+\dfrac{7}{3}\right)+\dfrac{3}{50}=\left(\dfrac{7}{3}+\dfrac{3}{50}\right)+2019\)
\(y+\left(\dfrac{7}{3}+\dfrac{3}{50}\right)=\left(\dfrac{7}{3}+\dfrac{3}{50}\right)+2019\)
\(y-2019=\left(\dfrac{7}{3}+\dfrac{3}{50}\right)-\left(\dfrac{7}{3}+\dfrac{3}{50}\right)\)
\(y-2019=0\)
\(y=0+2019\)
\(y=2019\)
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