Câu hỏi của Mai Xuân Phong

Question

$x^3+6x^2+11x+6$

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Lightning Farron · Accepted Answer

$x^3+6x^2+11x+6$

$=x^3+5x^2+6x+x^2+5x+6$

$=x\left(x^2+5x+6\right)+\left(x^2+5x+6\right)$

$=\left(x+1\right)\left(x^2+5x+6\right)$

$=\left(x+1\right)\left(x^2+3x+2x+6\right)$

$=\left(x+1\right)\left[x\left(x+3\right)+2\left(x+3\right)\right]$

$=\left(x+1\right)\left(x+2\right)\left(x+3\right)$Câu trả lời: $x^3+6x^2+11x+6$

$=x^3+5x^2+6x+x^2+5x+6$

$=x\left(x^2+5x+6\right)+\left(x^2+5x+6\right)$

$=\left(x+1\right)\left(x^2+5x+6\right)$

$=\left(x+1\right)\left(x^2+3x+2x+6\right)$

$=\left(x+1\right)\left[x\left(x+3\right)+2\left(x+3\right)\right]$

$=\left(x+1\right)\left(x+2\right)\left(x+3\right)$

qwerty · Answer

$x^3+6x^2+11x+6$

$=x^3+x^2+5x^2+5x+6x+6$

$=x^2\cdot\left(x+1\right)+5x\cdot\left(x+1\right)+6\left(x+1\right)$

$=\left(x+1\right)\cdot\left(x^2+5x+6\right)$

$=\left(x+1\right)\cdot\left(x^2+3x+2x+6\right)$

$=\left(x+1\right)\cdot\left(x\cdot\left(x+3\right)+2\left(x+3\right)\right)$

$=\left(x+1\right)\left(x+2\right)\left(x+3\right)$Câu trả lời: $x^3+6x^2+11x+6$

$=x^3+x^2+5x^2+5x+6x+6$

$=x^2\cdot\left(x+1\right)+5x\cdot\left(x+1\right)+6\left(x+1\right)$

$=\left(x+1\right)\cdot\left(x^2+5x+6\right)$

$=\left(x+1\right)\cdot\left(x^2+3x+2x+6\right)$

$=\left(x+1\right)\cdot\left(x\cdot\left(x+3\right)+2\left(x+3\right)\right)$

$=\left(x+1\right)\left(x+2\right)\left(x+3\right)$

Mai Thành Đạt · Answer

(x+3)(x+1)(x+2)Câu trả lời: (x+3)(x+1)(x+2)

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