Question

(X:3-4).5=15

128-3.(x+4)=23

(3x-2⁴).7³=2.7⁴

5x+x=39-3¹¹:3⁹

Answer 1

a) (x : 3 - 4) . 5 = 15

x : 3 - 4 = 15 : 5

x : 3 - 4 = 3

x : 3 = 3 + 4

x : 3 = 7

x = 7 . 3

x = 21.

b) 128 - 3 . (x + 4) = 23

3 . (x + 4) = 128 - 23

3 . (x + 4) = 105

x + 4 = 105 : 3

x + 4 = 35

x = 35 - 4

x = 31.

c) (3x - 2⁴) . 7³ = 2 . 7⁴

3x - 2⁴ = 2 . 7⁴ : 7³

3x - 2⁴ = 2 . 7

3x - 16 = 14

3x = 14 + 16

3x = 30

x = 30 : 3

x = 10.

d) 5x + x = 39 - 3¹¹ : 3⁹

5x + x = 39 - 3²

5x + x = 39 - 9

6x = 30

x = 30 : 6

x = 5.

Answer 2

a) \(\left(\dfrac{x}{3}-4\right).5=15\)

\(\Leftrightarrow\dfrac{x}{3}-4=\dfrac{15}{5}\)

\(\Leftrightarrow\dfrac{x}{3}-4=3\)

\(\Leftrightarrow\dfrac{x}{3}=3+4\)

\(\Leftrightarrow\dfrac{x}{3}=7\)

\(\Leftrightarrow x=7.3\)

\(\Leftrightarrow x=21\)

Vậy \(x=21\)

b) \(128-3\left(x+4\right)=23\)

\(\Leftrightarrow3\left(x+4\right)=128-23\)

\(\Leftrightarrow3\left(x+4\right)=105\)

\(\Leftrightarrow x+4=\dfrac{105}{3}\)

\(\Leftrightarrow x+4=35\)

\(\Leftrightarrow x=35-4\)

\(\Leftrightarrow x=31\)

Vậy \(x=31\)

c) \(\left(3x-2^4\right).7^3=2.7^4\)

\(\Leftrightarrow3x-2^4=\dfrac{2.7^4}{7^3}\)

\(\Leftrightarrow3x-2^4=2.7\)

\(\Leftrightarrow3x-2^4=14\)

\(\Leftrightarrow3x-16=14\)

\(\Leftrightarrow3x=14+16\)

\(\Leftrightarrow3x=30\)

\(\Leftrightarrow x=\dfrac{30}{3}\)

\(\Leftrightarrow x=10\)

Vậy \(x=10\)

d) \(5x+x=39-3^{11}:3^9\)

\(\Leftrightarrow6x=39-3^{11-9}\)

\(\Leftrightarrow6x=39-3^2\)

\(\Leftrightarrow6x=39-9\)

\(\Leftrightarrow6x=30\)

\(\Leftrightarrow x=\dfrac{30}{6}\)

\(\Leftrightarrow x=5\)

Vậy \(x=5\)