Question

x\(^2\)-2x+1=3x(x-1)

giải pt

Answer 1

\(x^2-2x+1=3x\left(x-1\right)\)

\(\Leftrightarrow\left(x-1\right)^2-3x\left(x-1\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(x-1-3x\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\-2x-1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{1}{2}\end{matrix}\right.\)

Vậy..............................................

Answer 2

\(x^2-2x+1=3x\left(x-1\right)\)

\(< =>\left(x-1\right)^2-3x\left(x-1\right)=0\)

\(< =>\left(x-1\right)\left(x-1-3x\right)=0\)

\(< =>\left(x-1\right)\left(-2x-1\right)=0\)

\(< =>\left[{}\begin{matrix}x-1=0\\-2x-1=0\end{matrix}\right.\)

\(< =>\left[{}\begin{matrix}x=1\\x=\dfrac{-1}{2}\end{matrix}\right.\)

S=\(\left\{1,\dfrac{-1}{2}\right\}\)