Question

x¹⁰= 1^x

2^x - 15 = 17

tìm x

Answer 1

a) Ta có :

\(x^{10}=1^x\)

Mà \(1^x=1\)

\(\Leftrightarrow x^{10}=1\)

\(\Leftrightarrow x^{10}=1^{10}\)

\(\Leftrightarrow x=1\left(tm\right)\)

Vậy .............

b) \(2^x-15=17\)

\(\Leftrightarrow2^x=17+15\)

\(\Leftrightarrow2^x=32\)

\(\Leftrightarrow2^x=2^5\)

\(\Leftrightarrow x=5\left(tm\right)\)

Vậy ...................

Answer 2

x¹⁰ = 1^x
<=> x¹⁰ = 1
<=> x¹⁰ = 1¹⁰
<=> x = 1
2^x - 15 = 17
<=> 2^x = 32
<=> 2^x = 2⁵
<=> x = 5
@nguyen thi mai linh

Answer 3

x^10=1^x

x^10=1

x^10=1^10

Suy ra x=1

2^x - 15 = 17

2^x=17+15

2^x=32

2^x=2^5

Suy ra x=5