Question

viết PTHH của chuỗi sau:

CaC2 -> C2H2 -> C2H4 -> C2H5OH ->CH3COOC2H5

Answer 1

CaC₂ + 2H₂O => C₂H₂ + Ca(OH)₂

C₂H₂ + H₂ => (t^o,Pd) C₂H₄

C₂H₄ + H2O => (H2SO4, t^o <140^oC>) C₂H₅OH

C₂H₅OH + CH3COOH <pứ hai chiều> xt: H2SO4, t^o => CH3COOC2H5 + H2O

Answer 2

\(CaC_2+2H_2O\rightarrow Ca\left(OH\right)_2+C_2H_2\uparrow\)

\(C_2H_2+H_2\xrightarrow[t^o]{Pd}C_2H_4\)

\(C_2H_4+H_2O\underrightarrow{axit}C_2H_5OH\)

\(C_2H_5OH+CH_3COOH\underrightarrow{H_2SO_4d}CH_3COOC_2H_5+H_2O\)

Answer 3

CaC₂+ 2H₂O\(\rightarrow\) Ca(OH)₂+ C₂H₂\(\uparrow\)

C₂H₂+ H₂\(\xrightarrow[to]{Pd}\) C₂H₄

C₂H₄+ H₂O\(\xrightarrow[]{axit}\) C₂H₅OH

C₂H₅OH+ CH₃COOH\(⇌\)( H₂SO₄ đặc, t^o) CH₃COOC₂H₅+ H₂O