Question

Viết kq dưới dạng lũy thừa: 3² . \(\frac{1}{243}\) . 81² . \(\frac{1}{3^2}\)

Answer 1

ta có : \(3^2.\frac{1}{243}.81^2.\frac{1}{3^2}=\frac{3^2.\left(3^4\right)^2}{3^5.3^2}=\frac{3^2.3^8}{3^5.3^1}=3^3\)

Answer 2

Ta có: \(3^2.\frac{1}{243}.81^2.\frac{1}{3^2}\)

\(=3^2.\frac{1}{3^5}.\left(3^4\right)^2.\frac{1}{3^2}\)

\(=\left(3^2.\frac{1}{3^2}\right).\frac{1}{3^5}.3^8\)

\(=1.\frac{3^8}{3^5}\)

\(=3^3\)

Chuk pạn hok tốt!

Answer 3

3² .1/243.81² .1/3² =27=3³

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