a) Ta có: \(\widehat{AOB}+\widehat{BOC}=\widehat{AOC}\)
\(\Rightarrow30^o+\widehat{BOC}=75^o\)
\(\Rightarrow\widehat{BOC}=45^o\)
b) Đề sai, sửa lại: Tính \(\widehat{DOC}\)
Lại có: \(\widehat{BOC}+\widehat{COD}=180^o\) (kề bù)
\(\Rightarrow45^o+\widehat{COD}=180^o\)
\(\Rightarrow\widehat{COD}=135^o\).