Question

Tính

a, A = 3 + 3² + 3³ + ... + 3²⁰¹⁶

b, \(2^{2^{2^2}}\)

Lm đc bài nào thì lm giùm nha

Answer 1

b, = 65536

Answer 2

A= 3+3²+3³+...+3²⁰¹⁶

3A=3²+3³+3⁴+....+3²⁰¹⁷

3A-A=(3²+3³+3⁴+...+3²⁰¹⁷)-(3+3²+3³+...+3²⁰¹⁶)

2A=3²⁰¹⁷-3

A=\(\frac{3^{2017}-3}{2}\)

Answer 3

b) \(2^{2^{2^2}}=4^{2^2}=16^2=256\)

Answer 4

Ta có: 

A = 3 + 3² + 3³ + .......+ 3²⁰¹⁶

=> 3A = 3² + 3³ + 3⁴ + .....+ 3²⁰¹⁷

Do đó 3A - A = 3²⁰¹⁷ - 3

               2A    = 3²⁰¹⁷ - 3

                  A   = \(\frac{3^{2017}-3}{2}\)

Answer 5

b) 65536

Answer 6

b, 65536