\(\dfrac{3x^5+5x^3+1}{4x^4-7x^2+2}.\dfrac{x}{2x+3}.\dfrac{4x^4-7x^2+2}{3x^5+5x^3+1}\) ( sửa đề )
\(=\left[\dfrac{3x^5+5x^3+1}{4x^4-7x^2+2}.\dfrac{4x^4-7x^2+2}{3x^5+5x^3+1}\right].\dfrac{x}{2x+3}\)
\(=\dfrac{x}{2x+3}\)
a \(\dfrac{25x^3y}{7z}\cdot\dfrac{28z}{15x^2y^5}\)
b \(\dfrac{x^2+3x+9}{2x+10}\cdot\dfrac{x+5}{x^3+27}\)
c \(\dfrac{3x-6}{x-1}\cdot\dfrac{1-x^3}{10-5x}\)
d \(\dfrac{3x-2}{x^2+1}\cdot\dfrac{x-1-x^2}{4-9x^2}\)
Làm phép tính nhân phân thức :
a) \(\dfrac{30x^3}{11y^2}.\dfrac{121y^5}{25x}\)
b) \(\dfrac{24y^5}{7x^2}.\left(-\dfrac{21x}{12y^3}\right)\)
c) \(\left(-\dfrac{18y^3}{25x^4}\right).\left(-\dfrac{15x^2}{9y^3}\right)\)
d) \(\dfrac{4x+8}{\left(x-10\right)^3}.\dfrac{2x-20}{\left(x+2\right)^2}\)
e) \(\dfrac{2x^2-20x+50}{3x+3}.\dfrac{x^2-1}{4\left(x-5\right)^3}\)
Thực hiện các phép tính sau :
a) \(\dfrac{15x}{7y^3}.\dfrac{2y^2}{x^2}\)
b) \(\dfrac{4y^2}{11x^4}.\left(-\dfrac{3x^2}{8y}\right)\)
c) \(\dfrac{x^3-8}{5x+20}.\dfrac{x^2+4x}{x^2+2x+4}\)
Rút gọn biểu thức :
a) \(\dfrac{x^4+15x+7}{2x^3+2}.\dfrac{x}{14x^2+1}.\dfrac{4x^3+4}{x^4+15x+7}\)
b) \(\dfrac{x^7+3x^2+2}{x^3-1}.\dfrac{3x}{x+1}.\dfrac{x^2+x+1}{x^7+3x^2+2}\)
Rút gọn biểu thức (chú ý dùng quy tắc đổi dấu để thấy nhân tử chung)
a) \(\dfrac{x+3}{x^2-4}.\dfrac{8-12x+6x^2-x^3}{9x+27}\)
b) \(\dfrac{6x-3}{5x^2+x}.\dfrac{25x^2+10x+1}{1-8x^3}\)
c) \(\dfrac{3x^2-x}{x^2-1}.\dfrac{1-x^4}{\left(1-3x\right)^3}\)
thực hiện phép tính :
a) 5x+10/10xy^2 nhân 12x/x+2
b) x-4/3x-1 nhân 9x-3/x^2-16
c)4x+2/(x+4)^2/ chia 3(x+3)/x+4
d)5x-5/3x+3 chia x-1/x+1
Thực hiện các phép tính sau (chú ý về dấu)
a) \(\dfrac{5x+10}{4x-8}.\dfrac{4-2x}{x+2}\)
b) \(\dfrac{x^2-36}{2x+10}.\dfrac{3}{6-x}\)
\(\dfrac{x^2+xy}{5x^2-5y^2}.\dfrac{3x^3-3y^3}{x^2-xy}\)
help me all bro
1.Thực hiện phép tính:
a) ( \(\dfrac{1}{1-x}\)- 1)( x - \(\dfrac{1-2x}{1-x}\) + 1)
b) ( \(\dfrac{1}{x}\)+ \(\dfrac{x-2}{x^2-4}\) - \(\dfrac{2+x}{x^2+2x}\))
c) ( \(\dfrac{2+x}{2-x}\) - \(\dfrac{4x^2}{x^2-4}\) - \(\dfrac{2-x}{2+x}\)): \(\dfrac{x^2-3x}{2x^2-x^3}\)
d) [ \(\dfrac{1}{x^2}\) + \(\dfrac{1}{y^2}\) + \(\dfrac{2}{x+y}\)( \(\dfrac{1}{x}\) + \(\dfrac{1}{y}\))] : \(\dfrac{x^3+y^3}{x^2y^2}\)
