Question

Tính nhanh:

(\(^{2^{100}}\)+\(^{2^{101}}\)+\(^{2^{102}}\)):(\(^{2^{97}}\)+\(^{2^{98}}\)+\(^{2^{99}}\))

Answer 1

Tui ra kết quả khác.

Tính nhanh:

\(\left(2^{100}+2^{101}+2^{102}\right):\left(2^{97}+2^{98}+2^{99}\right)\\ =2^3\left(2^{97}+2^{98}+2^{99}\right):\left(2^{97}+2^{98}+2^{99}\right)\\ =2^3=8\)

Answer 2

Giải:

\(\left(2^{100}+2^{101}+2^{102}\right):\left(2^{97}+2^{98}+2^{99}\right).\)

\(=\left(2^3.2^{97}+2^3.2^{98}+2^3.2^{99}\right):\left(2^{97}+2^{98}+2^{99}\right).\)

\(=2^3\left(2^{97}+2^{98}+2^{99}\right):\left(2^{97}+2^{98}+2^{99}\right).\)

\(=2^3\left[\left(2^{97}+2^{98}+2^{99}\right):\left(2^{97}+2^{98}+2^{99}\right)\right].\)

\(=2^3.1.\)

\(=2^3\left(=8\right).\)

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Answer 3

\(\left(2^{100}+2^{101}+2^{102}\right):\left(2^{97}+2^{98}+2^{99}\right)\)

\(=\left(2^{100+101+102}\right):\left(2^{97+98+99}\right)\)

\(=2^{303}:2^{294}=2^9\)

Answer 4

@Ace Legona hi xóa bài r . Hồi lớp 6 ngu lắm h làm bài này thử . Ko ngờ bị ném đá