\(\left(1+\dfrac{1}{2.4}\right)\left(1+\dfrac{1}{3.5}\right)\left(1+\dfrac{1}{4.6}\right)...\left(1+\dfrac{1}{99.101}\right)\)
\(=\dfrac{3^2}{2.4}.\dfrac{4^2}{3.5}.\dfrac{5^2}{4.6}...\dfrac{100^2}{99.101}\)
\(=\dfrac{3^2.4^2.5^2...100^2}{2.3.4^2.5^2...99^2.100.101}\)
\(=\dfrac{3^2.100^2}{2.3.100.101}\)
\(=\dfrac{3.100}{2.101}\)
\(=\dfrac{300}{202}\)