Question

Tính đạo hàm của các hàm số sau:

a) \(y = \frac{{2x - 1}}{{x + 2}};\)                                

b) \(y = \frac{{2x}}{{{x^2} + 1}}.\)

Answer 1

tham khảo:

a)\(y'=\dfrac{\left(2\right)\left(x+2\right)-\left(2x-1\right)\left(1\right)}{\left(x+2\right)^2}\)

\(y'=\dfrac{5}{\left(x+2\right)^2}\)

b)\(y'=\dfrac{\left(2\right)\left(x^2+1\right)-\left(2x\right)\left(2x\right)}{\left(x^2+1\right)^2}\)

\(y'=\dfrac{2\left(1-x^2\right)}{\left(x^2+1\right)^2}\)