Question

tính

\(8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)\)

Answer 1

\(8\dfrac{2}{7}-\left(3\dfrac{4}{9}+4\dfrac{2}{7}\right)\)

=\(8\dfrac{2}{7}-3\dfrac{4}{9}-4\dfrac{2}{7}\)

=\(\left(8\dfrac{2}{7}-4\dfrac{2}{7}\right)-3\dfrac{4}{9}\)

=\(\left[\left(8-4\right)+\left(\dfrac{2}{7}-\dfrac{2}{7}\right)\right]-3\dfrac{4}{9}\)

= [4+0]-\(3\dfrac{4}{9}\)

= 4-\(3\dfrac{4}{9}\)

=\(\dfrac{5}{9}\)

Tick cho mình nha

Answer 2

16/7-(31/9+30/7)

=16/7-487/63

=-49/9