Question

Tìm x:

\(\left(x-1\right)^3-2\left(x-1\right)\left(x+2\right)=\left(x+2\right)^3-3\left(x-1\right)^2+2\left(x+2\right)^2\)

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Answer 1

\(\left(x^3-3x^2+3x-1\right)-\left(2x^2+x-2\right)=\left(x^3+6x^2+12x+8\right)-\left(3x^2-6x+3\right)+\left(2x^2+8x+8\right)\)

\(-10x^2-24x-12=0\)

\(5x^2+12x+6=0\)

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