Tìm x:
a)-23+0,5x=1,5
-8+0,5x = 1,5
0,5x = 1,5-(-8) = 9,5
x = 9,5:0,5 = 19
b)(−3)x81=−27
(-3)x:81 =-27
(-3)x = -27.81 = -2187
(-3)x = (-3)7
=> x=7
c)112.x−4=0,5
1,5.x = 0,5+4 = 4,5
x = 4,5:1,5 = 3
d)123:x4=6:0,3
\(\frac{5}{3}\):\(\frac{x}{4}\) = 20
\(\frac{x}{4}\) = \(\frac{5}{3}\):20 = \(\frac{1}{12}\)
=> x:4 = \(\frac{1}{12}\)
x = \(\frac{1}{12}\).4 = \(\frac{1}{3}\)
\(a,\left(-3\right)^{x+3}=-\frac{1}{27}\)
\(b,\left(-6\right)^{2x+2}=\frac{1}{36}\)
\(c,\left(-3\right)^{x+5}=\frac{1}{81}\)
\(d,\left(\frac{1}{9}^x\right)=\left(\frac{1}{27}\right)^6\)
\(e,\left(\frac{4}{9}\right)^x=\left(\frac{8}{27}\right)^6\)
\(f,5^{x+4}-3.5^{x+3}=2.5^{11}\)
\(r,4.3^{x-1}+2.3^{x+2}=4.3^6+2.3^9\)
\(h,\left(\frac{1}{2}-\frac{1}{3}\right).6x+6^{x+2}=6^{10}+6^7\)
nhờ mấy bn giúp mk tối mình nộp rồi
Tìm x \(\in\) Z
a,\(\frac{1}{2}-\left(\frac{1}{3}+\frac{1}{4}\right)< x< \frac{1}{48}-\left(\frac{1}{16}-\frac{1}{6}\right)\)
b, \(\frac{3}{4}-\frac{5}{6}\le\frac{x}{12}< 1-\left(\frac{2}{3}-\frac{1}{3}\right)\)
c, \(x:\left(\frac{1}{2}\right)^2=\frac{-1}{2}\)
d,\(\left(x^4\right)^2=\frac{x^{12}}{x^5}\left(x\ne0\right)\)
e,\(\frac{3^2.3^8}{27^3}=3^x\)
f,\(2^{x-1}=\left(16\right)^5\)
\(a,\left|x-\frac{2}{5}\right|=0,5-\left(-\frac{1}{2}\right)\)
\(b,\frac{3}{2}\left|\frac{1}{4}-x\right|=\frac{5}{6}-1\)
\(c,\frac{4}{3}-\frac{5}{3}\left|x-\frac{1}{3}\right|=-\frac{1}{6}\div\frac{2}{3}\)
tìm x biết:
a) \(\left|x+0,573\right|=2\)
b)\(\left|x+\frac{1}{3}\right|-4=\left(-1\right)\)
c)\(1,5.\left|3x-1\right|+4,659=9,103\)
d) \(\left[\frac{\left(x-4\frac{1}{2}\right):0,003}{\left(3\frac{1}{20}-2,65\right).4:\frac{1}{5}}-\frac{\left(0,3-\frac{3}{20}\right).1\frac{1}{2}}{\left(1,88+2\frac{3}{25}\right):\frac{1}{8}}\right]:62\frac{1}{20}+17,81:0,0131-1301=0\)
1. Tính.
a) \(\left(\frac{2}{3}\right)^3\) b) \(\left(-2\frac{3}{4}\right)^2\) c) (0,6)\(^4\) d) \(\left(\frac{-1}{2}\right)^4\) e) \(\left(\frac{-1}{2}\right)^5\)
2. viết mỗi số \(\frac{81}{125}\) ; \(\frac{-8}{27}\) dưới dạng 1 lũy thừa.
b) viết các số: (0,36)\(^3\) : b) \(\left(-\frac{4}{11}\right)^2\) : c) (0,5)\(^4\) . 6\(^4\) : d) \(\left(\frac{2}{5}\right)^5.x=\left(\frac{2}{5}\right)^8\)
3. tìm x
a) x : \(\left(\frac{3}{4}\right)^3=\left(\frac{3}{4}\right)^2\) b) \(\left(\frac{2}{5}\right)^5.x=\left(\frac{2}{5}\right)^8\)
giúp mk nhé mai mk nộp bài tp r thanks
Bài 2:
a)\(x+\frac{1}{3}=\frac{3}{4}\)
b)\(\left|x+\frac{1}{8}\right|-\frac{1}{6}=0\)
c)\(\frac{x}{27}=-\frac{2}{36}\)
d)\(\left(x+\frac{1}{2}\right)^2=\frac{1}{16}\)
Thực hiện phép tính:
a) \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}\)
b)\(-12:\left(\frac{3}{4}-\frac{5}{6}\right)^2\)
c)\(\frac{7}{23}.\left[\left(\frac{-8}{6}\right)-\frac{45}{18}\right]\)
d)\(23\frac{1}{4}.\frac{7}{5}-13\frac{1}{4}:\frac{5}{7}\)
e)\(\left(1+\frac{2}{3}-\frac{1}{4}\right).\left(0,8-\frac{3}{4}\right)^2\)
Tính:
a)\(\left\{\left[\left(6,2:0,31-\frac{5}{6}.0,9\right).0,2+0,15\right]:0,2\right\}:\left[\left(2+1\frac{4}{11}:0,1\right).\frac{1}{33}\right]\)
b)\(0,4\left(3\right)+0,6\left(2\right)-2\frac{1}{2}.\left[\left(\frac{1}{2}+\frac{1}{3}:0,5\left(8\right)\right)\right]:\frac{50}{53}\)
c)\(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}\)
1) Tìm x
a) 4,5 : 0,3 = 2,25 : (0,1 . x)
b) 8 : \(\left(\frac{1}{4}.x\right)\) = 2 : 0,02
c) 3 : \(2\frac{1}{4}\) = \(\frac{3}{4}\) : (6 . x)