Question

tìm x y thuộc z biết 2xy+3x=4 : 16x^4-72x^2+90

Answer 1

2xy+3x = 4 : \(16x^4-72x^2+90\)

=> 2+3(\(x^2y\)) = (16-72+90)\(x^6\)

=>5\(x^2y\) = \(34x^6\)