Question

tìm x

(x²-2x+1)-4=0

Answer 1

\(\left(x^2-2x+1\right)-4=0\\ \Leftrightarrow\left(x-1\right)^2-2^2=0\\ \Leftrightarrow\left(x-1-2\right)\left(x-1+2\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-3=0\\x+1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

Vậy \(x=3;x=-1\) là nghiệm của pt.

Answer 2

\(\left(x^2-2x+1\right)-4=0\)

\(\left(x-1\right)^2-2^2=0\)

\(\left(x-1-2\right)\left(x-1+2\right)=0\)

\(\left(x-3\right)\left(x+1\right)=0\)

\(\left[{}\begin{matrix}x-3=0\\x+1=0\end{matrix}\right.\)

\(\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

Answer 3

\(\left(x^2-2x+1\right)-4=0\)

\(\Leftrightarrow\left(x-1\right)^2-2^2=0\)

\(\Leftrightarrow\left(x-1-2\right)\left(x-1+2\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

Vậy............

Answer 4

(x² - 2x + 1) - 4 = 0

(x - 1)² - 2² = 0

(x - 1 - 2)(x - 1 + 2) = 0

(x - 3)(x + 1) = 0

\(\Leftrightarrow \begin{bmatrix} x - 3 = 0 & & \\ x + 1 = 0 & & \end{bmatrix}\) (bỏ dấu ngoặc bên phải nha pn)

\(\Leftrightarrow \begin{bmatrix} x = 3 & & \\ x = - 1 & & \end{bmatrix}\)

Vậy x = 3; x = - 1

Answer 5

\(\left(x^2-2x+1\right)-4=0\)

\(\Leftrightarrow\left(x-1\right)^2-2^2=0\)

\(\Leftrightarrow\left(x-1-2\right)\left(x-1+2\right)=0\)

\(\Leftrightarrow\left(x-1-2\right)=0\) hoặc \(\left(x-1+2\right)=0\)

\(\left\{{}\begin{matrix}x-1-2=0\Rightarrow x=3\\x-1+2=0\Rightarrow x=-1\end{matrix}\right.\)

Vậy ....

Answer 6

(x²-2x+1)-4=0

=> (x-1)²-2²=0

=> ( x-1-2)(x-1+2)=0

=>(x-3)(x+1)=0

=>\(\left[{}\begin{matrix}x-3=0\\x+1=0\end{matrix}\right.\) =>\(\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)

vậy x \(\in\) {-1;3}

Answer 7

=\(\left(x-1\right)^2-2^2\)=0

=\(\left(x-1+2\right)\left(x-1-2\right)\)=0

=\(\left(x+1\right)\left(x-3\right)\)=0

\(\rightarrow\)\(x+1=0\) hoặc \(x-3=0\)

\(\rightarrow x=-1\) hoặc \(x=3\)

Answer 8

\(\left(x^2-2x+1\right)-4=0 \)

\(\Leftrightarrow\left(x-1\right)^2=4\)

\(\Leftrightarrow x-1=2\)

\(\Leftrightarrow x=3\)