Question

tìm x: \(\frac{x+3}{4}\)=\(\frac{x-1}{2}\)

Answer 1

\(\frac{x+3}{4}=\frac{x-1}{2}\)

\(2\left(x+3\right)=4\left(x-1\right)\)

\(2x+6=4x-4\)

\(4x-2x=4+6\)

\(2x=10\)

\(x=\frac{10}{2}\)

\(x=5\)

Answer 2

\(\frac{x+3}{4}=\frac{x-1}{2}\)

\(\Rightarrow2.\left(x+3\right)=4.\left(x-1\right)\)

\(\Rightarrow2x+6=4x-4\)

\(2x-4x=-4-6\)

\(-2x=-10\)

\(x=5\)

Vậy \(x=5\)

Answer 3

\(\Leftrightarrow\)\(4\left(x-1\right)=2\left(x+3\right)\)

\(\Leftrightarrow4x-4=2x+6\)

\(\Leftrightarrow2x=10\)

\(\Leftrightarrow x=5\)

Answer 4

\(\frac{x+3}{4}\)=\(\frac{x-1}{2}\)

\(\Leftrightarrow\)2.(x+3)=4.(x-1) * tính chất nhân chéo*

2x+6 =4x-4

6+4 =4x-2x

10 =2x

x =10:2

x =5