\(\eqalign{ & \left| {x - 2} \right| - 2x = - 1 \cr & T{H_1}:x - 2 \geqslant 0 \Rightarrow x \geqslant 2 \cr & x - 2 - 2x = - 1 \cr & \Leftrightarrow - x = - 1 + 2 \cr & \Leftrightarrow - x = 1 \cr & \Leftrightarrow x = - 1\left( {KTM} \right) \cr & T{H_2}:x - 2 < 0 \Rightarrow x < 2 \cr & - \left( {x - 2} \right) - 2x = - 1 \cr & \Leftrightarrow - x + 2 - 2x = - 1 \cr & \Leftrightarrow - 3x = - 1 - 2 \cr & \Leftrightarrow - 3x = - 3 \cr & \Leftrightarrow x = \frac{{ - 3}}{{ - 3}} = 1\left( {TM} \right) \cr}\)
Vậy \(x=1\)
(x-2)-2x = -1
x-2-2x = -1
x-2x = 1
-x = 1
x = -1
Chúc bạn học tốt =))
(x-2)-2x = -1
x-2-2x = -1
x-2x = 1
-x = 1
x = -1