Question

Tìm x biết

a,(2x-3)^2=1

 

Answer 1

a) \(\left(2x-3\right)^2=1\)

\(\left(2x-3\right)^2=\left(\pm1\right)^2\)

\(\Rightarrow\begin{cases}2x-3=1\\2x-3=-1\end{cases}\)

\(\Rightarrow\begin{cases}2x=1+3\\2x=-1+3\end{cases}\)

\(\Rightarrow\begin{cases}2x=4\\2x=2\end{cases}\)

\(\Rightarrow\begin{cases}x=4:2\\x=2:2\end{cases}\)

\(\Rightarrow\begin{cases}x=2\\x=1\end{cases}\)

Vậy \(x\in\left\{2;1\right\}\)

Answer 2

\(\left(2x-3\right)^2=1\)

\(\Rightarrow\left(2x-3\right)^2=\left(\pm1\right)\)

\(\Rightarrow\begin{cases}2x-3=1\\2x-3=-1\end{cases}\)

\(\Rightarrow\begin{cases}2x=4\\2x=2\end{cases}\)

\(\Rightarrow\begin{cases}x=2\\x=1\end{cases}\)

Vậy :        \(x\in\left\{1;2\right\}\)

Answer 3

\(\left(2x-3\right)^2=1\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}2x-3=1\Rightarrow x=2\\2x-3=-1\Rightarrow x=1\end{array}\right.\)

Vậy...

Answer 4

(2x-3)^2=1

=))(2x-3)^2=1^2 hoặc (2x-3)^2=(-1)^2

=))2x-3=1 hoặc 2x-3=-1

=))2x=4 hoặc 2x=2

=))x=2 hoặc x=1

Answer 5

(2x-3)^2=1^2

2x-3 =1

2x =1+3

2x =4

x =4/2

x =2