\(\left|x-2,2\right|=\left|0,2+x\right|\)
\(\Rightarrow\left\{{}\begin{matrix}x-2,2=0,2+x\\x-2,2=-0,2-x\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x-x=0,2+2,2\\x+x=-0,2+2,2\end{matrix}\right.\)
\(\Rightarrow\left\{{}\begin{matrix}0x=2,4\\2x=-2\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x\in\varnothing\\x=-1\end{matrix}\right.\)
Vậy...........
Chúc bạn học tốt!!!
\(\left|x-2,2\right|=\left|0,2+x\right|\)
Bình phương vế ta có:
\(\left(\left|x-2,2\right|\right)^2=\left(\left|0,2+x\right|\right)^2\)
\(\Leftrightarrow0,04\left(25x^2-110x+121\right)=0,04\left(25x^2+10x+1\right)\)
\(\Leftrightarrow25x^2-110x+121=25x^2+10x+1\)
\(\Leftrightarrow120x=120\Rightarrow x=1\)
Vậy x=1
Bn tham khảo nhé