Câu 1: \(\frac{5}{12}-\left(\frac{7}{3}-x\right)=\frac{8}{9}\)
=> \(\left(\frac{7}{3}-x\right)=\frac{5}{12}-\frac{8}{9}\)
=> \(\frac{7}{3}-x=-\frac{17}{36}\)
=> \(x=\frac{7}{3}-\left(-\frac{17}{36}\right)\)
=> \(x=\frac{101}{36}\)
Vậy \(x=\frac{101}{36}.\)
Câu 3: \(\frac{5}{6}+\frac{1}{6}:x=\frac{4}{5}\)
=> \(\frac{1}{6}:x=\frac{4}{5}-\frac{5}{6}\)
=> \(\frac{1}{6}:x=-\frac{1}{30}\)
=> \(x=\frac{1}{6}:\left(-\frac{1}{30}\right)\)
=> \(x=-5\)
Vậy \(x=-5.\)
Còn mấy câu sau bạn làm tương tự nhé.
Chúc bạn học tốt!
1) \(\frac{5}{12}\)- (\(\frac{7}{3}\)- x) = \(\frac{8}{9}\)
\(\frac{7}{3}\)- x = \(\frac{-17}{36}\)
=> x = \(\frac{101}{36}\)
3) \(\frac{5}{6}\)+ \(\frac{1}{6}\): x = \(\frac{4}{5}\)
\(\frac{1}{6}\): x = \(\frac{-1}{30}\)
=> x = -5
4) \(\frac{6}{7}\)+ \(\frac{1}{7}\). x = \(\frac{3}{4}\)
\(\frac{1}{7}\). x = \(\frac{-3}{28}\)
=> x = \(\frac{-3}{4}\)
5) \(\frac{1}{3}\)+ \(\frac{2}{3}\): x = \(\frac{5}{9}\)
\(\frac{2}{3}\): x = \(\frac{2}{9}\)
=> x = 3
Bạn xem lại câu 2 đi nha. Mk ko hiểu đề bài câu 2 cho lắm
*Câu 1 : \(\frac{5}{12}\) - ( \(\frac{7}{3}\) - x ) = \(\frac{8}{9}\)
<=> ( \(\frac{7}{3}\) - x ) = \(\frac{-17}{36}\)
<=> x = \(\frac{101}{36}\)
Vậy x = \(\frac{101}{36}\).
*Câu 3 : \(\frac{5}{6}\) + \(\frac{1}{6}\) : x = \(\frac{4}{5}\)
<=> \(\frac{1}{6}\) : x = \(\frac{-1}{30}\)
<=> x = \(\frac{-1}{180}\)
Vậy x = \(\frac{-1}{180}\).
*Câu 2 : \(\frac{5}{2x}\) . ( 5 - 3x ) = 0
<=> \(\left[{}\begin{matrix}\frac{5}{2x}=0\\5-3x=0\end{matrix}\right.\)
<=> \(\left[{}\begin{matrix}5=0\left(loại\right)\\3x=5\end{matrix}\right.\)
<=> x = \(\frac{5}{3}\)
Vậy x = \(\frac{5}{3}\).
*Câu 4 : \(\frac{6}{7}\) + \(\frac{1}{7}\) . x = \(\frac{3}{4}\)
<=> \(\frac{x}{7}\) = \(\frac{-3}{28}\)
<=> x = \(\frac{-3}{4}\)
Vậy x = \(\frac{-3}{4}\).
*Câu 5 : \(\frac{1}{3}\) + \(\frac{2}{3}\) : x = \(\frac{5}{9}\)
<=> \(\frac{2}{3x}\) = \(\frac{2}{9}\)
<=> 3x = 9
<=> x = 3
Vậy x = 3.
Mong bạn tick!
\(\frac{-3}{4}\)\(\frac{5}{3}\)
