(x - \(\frac{1}{2}\))3 = \(\frac{1}{27}\)
=> x - \(\frac{1}{2}\) = \(\frac{1}{9}\)
=> x = \(\frac{1}{9}\) + \(\frac{1}{2}\) = \(\frac{11}{18}\)
\(\left(x-\frac{1}{1}\right)^3=\frac{1}{27}\)
Có \(\frac{1}{27}=\left(\frac{1}{3}\right)^3\)hoặc \(\frac{1}{27}=\left(-\frac{1}{3}\right)\)
\(\Rightarrow\)\(\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)hoặc \(\left(x-\frac{1}{2}\right)^3=\left(-\frac{1}{3}\right)^3\)
+TH1:\(\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
\(\Rightarrow\)\(x-\frac{1}{2}=\frac{1}{3}\)
\(x=\frac{1}{3}+\frac{1}{2}\)
\(x=\frac{5}{6}\)
+TH2:\(\left(x-\frac{1}{2}\right)^3=\left(-\frac{1}{3}\right)^3\)
\(\Rightarrow x-\frac{1}{2}=-\frac{1}{3}\)
\(x=-\frac{1}{3}+\frac{1}{2}\)
\(x=\frac{1}{6}\)
Vậy \(x=\frac{5}{6}hoạcx=\frac{1}{6}\)
\(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\)
\(\Rightarrow x-\frac{1}{2}=\frac{1}{9}\)
\(\Rightarrow x=\frac{1}{9}+\frac{1}{2}\)
\(\Rightarrow x=\frac{2}{18}+\frac{9}{18}\)
\(\Rightarrow x=\frac{11}{18}\)
Vậy \(x=\frac{11}{18}\)
\(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\)
\(\Rightarrow\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
\(\Rightarrow x-\frac{1}{2}=\frac{1}{3}\)
\(\Rightarrow x=\frac{1}{3}+\frac{1}{2}\)
\(\Rightarrow x=\frac{5}{6}\)
Vậy \(x=\frac{5}{6}.\)
Chúc bạn học tốt!
\(\left(x-\frac{1}{2}\right)^3=\frac{1}{27}\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)=\frac{1}{3}\)
\(\Leftrightarrow x=\frac{1}{3}+\frac{1}{2}\)
\(\Leftrightarrow x=\frac{5}{6}\)
