Question

Tìm x biết:

a) 3,6-|x-0, 4|=0

B) |x-3, 5|=7, 5

Giúp mìk vs

Answer 1

a) \(3,6-\left|x-0,4\right|=0\)

=> \(\left|x-0,4\right|=3,6\)

=> \(x-0,4=\pm3,6\)

=> \(x=\left\{4;-3,2\right\}\)

b) \(\left|x-3,5\right|=7,5\)

=> \(x-3,5=\pm7,5\)

=> \(x=\left\{11;-4\right\}\)

Answer 2

Giải:

a) \(3,6-\left|x-0,4\right|=0\)

\(\Leftrightarrow\left|x-0,4\right|=3,6\)

\(\Leftrightarrow\left[{}\begin{matrix}x-0,4=3,6\\x-0,4=-3,6\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-3,2\end{matrix}\right.\)

Vậy ...

b) \(\left|x-3,5\right|=7,5\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3,5=7,5\\x-3,5=-7,5\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=11\\x=-4\end{matrix}\right.\)

Vậy ...